Question

A particle is moving with speed 6m/s along the direction of A=2i+2j-k, then it's velocity is:​

Answer 1

Step-by-step explanation:

v = |v|/v(unit vector)

A = 2i +2j -k

|A|= √4+4+1

= 3

Unit vector = (2i +2j -k)/3

And velocity will be equal to=>

(2i +2j -k)× 1/3 × 6

4i +4j -2k

4i +4j -2kHope it helps uh