A particle is of weight 8 kg. When it is allowed to fall under the force of gravity its momentum at the time t = 2 sec would be
Answers
Answered by
0
v = u + gt
v = 0 + 10*2
v = 20 m/s
now momentum P = m *v
P= 8*20 = 160 kg m /sec answer
v = 0 + 10*2
v = 20 m/s
now momentum P = m *v
P= 8*20 = 160 kg m /sec answer
Similar questions