A particle is performing circular motion of radius 1 m. Its speed is v=(2t^(2)) m//s. What will be magnitude of its acceleration at t=1s.
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PHYSICS
A particle is performing circular motion of radius 1m. Its speed is v=(2t
2
)m/s. What will be magnitude of its acceleration at t=1s.
December 26, 2019avatar
Jain Nimbalkar
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ANSWER
Radial acceleration a
n
=v
2
/r
at t = 1s, v= 2 m/s a
n
=2
2
/1=4m/s
2
Tangential acceleration a
t
=dv/dt=4t
at t = 1 s, a
t
=4m/s
2
so, a=
a
n
2
+a
t
2
a=
4
2
+4
2
=4
2
m/s
2
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