Question

A particle is performing circular motion of radius 1 m. Its speed is v=(2t^(2)) m//s. What will be magnitude of its acceleration at t=1s.

Answer 1

Explanation:

PHYSICS

A particle is performing circular motion of radius 1m. Its speed is v=(2t

2

)m/s. What will be magnitude of its acceleration at t=1s.

December 26, 2019avatar

Jain Nimbalkar

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ANSWER

Radial acceleration a

n

=v

2

/r

at t = 1s, v= 2 m/s a

n

=2

2

/1=4m/s

2

Tangential acceleration a

t

=dv/dt=4t

at t = 1 s, a

t

=4m/s

2

so, a=

a

n

2

+a

t

2

a=

4

2

+4

2

=4

2

m/s

2