Question

A particle is projected at an angle theta=30 with the horizontal, with a velocity 10m/s then
A) after 2s the velocity of particle makes an angle of 60 with the initial velocity vector
B) after 1s the velocity of the particle makes an angle of 60 with the initial velocity vector
C) the magnitude of velocity of particle after 1s is 10m/s
D) the magnitude of velocity of particle after 1s is 5m/s

Answer 1

Vx=u cos theta = 10 × cos 30° =5√3

Vy = u sin theta - gt = 10 × sin 30° -10*1

= -5

Magnitude of velocity= √Vx^2 + Vy^2

=10 m/s

So option c is correct.