Question

A particle is projected at an angle θ with an inclined plane making an angle β with the horizontal as

shown in figure, speed of the particle is u, after time t find :

a) x component of acceleration ?

b) y component of acceleration ?

c) x component of velocity ?

d) y component of velocity ?

e) x component of displacement ?

f) y component of displacement ?

g) y component of velocity when particle is at maximum distance from the incline plane ?​

Answer 1

Answer:x=ucostheta

Y=usintheta

Explanation:

Answer 2

ANSWER:

All the values will be same as that of an projectile motion the only variable in this question is gravity.  

The gravity in this question has two components the first one being, the second one is the  

Therefore replacing the acceleration with the gravity components  

a) the X component of the gravity in terms of acceleration is given as g \sin \beta

b) the Y component of the gravity in terms of acceleration is given as g \cos \beta

c) the X component of the velocity is given as; with respect to the time $t = \mathrm{t}=u \sin \theta-g \sin \beta t$

d) the Y component of the velocity is given as; with respect to the time$t = u \sin \theta-g \cos \beta t$

e) the X component of the displacement is equal to the equation of $u \cos \theta t-\frac{1}{2} g \sin \beta t$

f) the Y component of the displacement is equal to the equation of $u \sin \theta t-\frac{1}{2} g \cos \beta t$

g) the peak distance from the inclined plane meaning the height that is maximum reached by the Y component of the velocity = 0