Question

A particle is projected from ground with speed 80m/s at an angle 30

Answer 1

u = 80 m/s

Angle (Theta) = 30°

If you are asking about Flight time of projectile (T), then=>

T = (2×u×sin theta)/g

T = (2×80×sin30°)/9.8

T = (160×1/2)/9.8

T = 8.16 sec....●

If you are asking Height of Projectile (h), then=>

h = (u^2×sin^2theta)/g

h = ( 80×80×1/2×1/2)/9.8

h = 1600/9.8

h = 163.26 m........●

If you are asking about the Range of Projectile (R), then=>

R = (u^2×sin2theta)/g

R = (80×80×2sin theta×cos theta)/g

R = (6400×2×1/2×√3/2)/9.8

R = 5542.56/9.8

R = 565.57 metres.......●

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