Question

A particle is projected from point a vertically upwards with a speed of 50 m/s and another is dropped simultaneously from B which is 200 metre vertically above A particles cross Each Other after ____ seconds

Answer 1

here for particle 1 that is it's above the point A
we get 200 = 5t^2
for 2 particle
200= 50t-5t^2
lhs is same so rhs has to be we get
5t^2=50t-5t^2
10t^2=50t
and hence we get 5secs