Question

A particle is projected from point a with velocity U root 2 at an angle 45 degree with horizontal as shown in figure it strikes the plane BC at right angles the velocity of the particle at the time of Collision is ​

Answer 1

Answer:

c. will be your correct answer

Explanation:

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Answer 2

Answer:

The horizontal component of the velocity remains the same=

2

ucos45

∘

=u

Let the vertical velocity of the particle when it strikes the plane be v downwards. Since it hits the plane perpendicularly, the final velocity forms an angle of 60

∘

with the vertical.

Thus

v

u

=tan60

∘

=

3

⟹v=

3

u

Thus the magnitude of the velocity when it hits the plane is

v

x

2

+v

y

2

=

u

2

+(

3

u

)

2

=

3

2u