Question

A particle is projected from point P with velocity 5 root 2 metre per second perpendicular to the surface of a hollow right angle cone whose axis is vertical . it collides at A normally the time of the flight of the particle is

Answer 1

Explanation:

Given A particle is projected from point P with velocity 5 root 2 metre per second perpendicular to the surface of a hollow right angle cone whose axis is vertical . it collides at A normally the time of the flight of the particle is

• So the given cone is a right angle cone and let the angle AOB = 90 degree.
• So angle of projection will be 45 degree through x axis. Velocity is normal to surface. Therefore angle below along x axis is also 45 degree.
• Now in y direction we have,
•                    So V = U + at we can write it as  
•             So – V sin 45 = U sin 45 – gt ---------1
• Now the velocity is constant since there is no acceleration.
•                      So u cos 45 = v cos 45
•                       Or u = v ---------------------------2
• So from 1 and 2 we get
•               So – u sin 45 = u sin 45 – gt
•                  Or gt = 2u sin 45
•                   Or t = 2u sin 45 / g
•                          = 2 x 5 √2 / 10  x 1 / √2  
•                   Or t = 1 sec.

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