A particle is projected from the ground with speed 30 m/s at an angle 60° with horizontal. The radius of curvature of the path of projectile, when its velocity makes an angle 30° with horizontal is
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radius of the curvature=half of the RANGE
range=u^2sin2theta/g
range=(900×root3/2)/10
=45root3
radius of curvature=(45root3)/2
=22.5root3
range=u^2sin2theta/g
range=(900×root3/2)/10
=45root3
radius of curvature=(45root3)/2
=22.5root3
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