Question

a particle is projected from the surface of moon with a velocity v at an angle 60 ^. from horizontal . if the paricle reaches the maximum height 5r/2 where r is the radius of moon then find the value of v {mass of moon is m}​

Answer 1

Answer:

Explanation:

Assume no air resistance and constant gravitational acceleration g.

Then the (constant) horizontal velocity is vH=vcos30∘=3√2v and the initial vertical velocity is vV=vsin30∘=12v.

We can work out the maximum height h from v2=u2+2as, so  h=v28g .

The angular momentum is mvHh=3√mv316g