a particle is projected from the surface of moon with a velocity v at an angle 60 ^. from horizontal . if the paricle reaches the maximum height 5r/2 where r is the radius of moon then find the value of v {mass of moon is m}
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Answer:
Explanation:
Assume no air resistance and constant gravitational acceleration g.
Then the (constant) horizontal velocity is vH=vcos30∘=3√2v and the initial vertical velocity is vV=vsin30∘=12v.
We can work out the maximum height h from v2=u2+2as, so h=v28g .
The angular momentum is mvHh=3√mv316g
mohit8895:
but the answer is root of 5GM/4R
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