Question

A particle is projected in the upword direction under gravity time of flight for particles is T.velocity of the particle at a hegist just half of the maximum height will be​

Answer 1

Answer:

V = 5T/√2

Explanation:

A particle is projected in the upword direction under gravity time of flight for particles is T.velocity of the particle at a hegist just half of the maximum height will be​

time of flight for particles is T

Time to recah Max height = T/2

Velocity at Top = 0

a = g = 10 m/s²

using V = u + at

0 = U  + (-10)(T/2)

=> U = 5T

Initial Velocity = 5T

Max Height =  Ut + (1/2)at²

= 5T(T/2) + (1/2)(-10)(T/2)²

= 5T²/2  - 5T²/4

= 5T²/4

Half of the Max height = 5T²/8

Using V² - U² = 2aS

=> V² - (5T)² = 2(-10)5T²/8

=> V² = -25T²/2 + 25T²

=> V² = 25T²/2

=> V = 5T/√2

velocity of the particle at a hegist just half of the maximum height will be​ = 5T/√2