Question

x³ + y³ = 18xy, find dy/dx​

Answer 1

Explanation:

dy/dx

3x²*1+3y²dy/dx=18(xdy/dx+y*1)

3x²+3y²dy/dx=18xdy/dx+18y

3y²dy/dx-18xdy/dx=18y-3x²

dy/fx(3y²-18x)=-3x²+18y

dy/dx=3(6y-x²)/3(y²-6x)

dy/dx=6y-x²/y²-6x

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