a particle is projected up along a rough plane of inclination 45 with the horizontal if the coeffecient of friction is 0.5, the retaradation is
1)g/2. 2) g/2√2 3) 3g/2√2. 4) g/√2
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weight component along down the incline is mgsin450 and friction down the incline isμmgcos450adding both and dividing by mass m we will get the net retardation means acceleration downward a=gsin450+μgcos450= 2223g
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