Question

A particle is projected vertically up from a top of a tower with velocity 10m/s it reaches ground in 5s find distance traversed of particle at groung

Answer 1

Given:

Initial velocity $\left( { v }_{ 0 } \right) = 10 m/s$

Time, t = 5 s

Solution:

Distance travelled = ?

$Distance\quad =\quad d\quad =\quad \frac { { v }_{ f }\quad -\quad { v }_{ i } }{ 2 } \quad \times \quad t$

$\Rightarrow \quad d\quad =\quad \frac { 0\quad -\quad 10 }{ 2 } \quad \times \quad5$

$\therefore \quad Distance\quad travelled\quad =\quad 25\quad m\quad \left( Neglect\quad the\quad negative\quad sign \right)$