A particle moving with non-zero velocity and constant acceleration on straight line travels 15m in first 3s and 33m in next 3 sec in the same direction,find initial velocity and acceleration of particle
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In the First 3 seconds, distance travelled = 15 m
∴ S = ut + 1/2 at²
⇒ 15 = 3u + 1/2 × a (3)³
∴ 6u + 9a = 30
2u + 3a = 10 -----eq(i).
Similarly, In Second case,
Total time = 3 + 3 = 6 seconds.
Total distance = 33 + 15 = 48 m.
∴ 48 = 6u + 1/2 × a × 36
⇒ 48 = 6u + 18a
u + 3a = 8 --------eq(ii)
Solving (i) and (ii).
a = 2 m/s². and u = 2 m/s.
Hope it Helps.
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