Question

A particle is projected with a velocity of 14 m/s at an angle of elevation . Find equation of path

Answer 1

Step-by-step explanation:

If angle of projection be θ then initial vertical velocity will be 50Sinθ

 so after 4s its height will be h=50Sinθ(4)−2g(4)2

Putting g=10m/s2 and h=20m we get Sinθ=21

so θ=300