Question

A particle is projected with a velocity of 30m/s at an angle theta with the horizontal,tan theta =3/4.After 1 second,direction of motion of the particle makes an angle alpha with horizontal,then tan alpha=

Answer 1

Tanx = 3/4
Sinx = 3/5
Cosx = 4/5

Along vertical after 1s
v = u + at
vSinα = 30Sinx - g
= 30*3/5 - 10
= 8 m/s —-(1)

Horizontal component of velocity will remain constant throughout the journey.
∴ vCosα = uCosx
vCosα = 30*4/5 = 24 —-(2)

Divide equation (1) by (2)
vSinα / vCos α = 8/24 = 1/3
Tan α = 1/3

Answer 2

Answer:

tan theta = 1 / 3

Explanation:

Assume , tanx is 3by 4 , sinx is 3 by 5