Question

a particle is projected with initial velocity v=2i+3j in x-y plane. the equation of trajectory of the particle is? ​

Answer 1

At any general instant

v in x direction = 2

displacement in (x) = 2t

t = x/2

v in y direction = 3 - gt

Displacement in (y) direction = 3t - (g/2)t²

Replace t by x/2 to get

y = 1.5x - gx²/8

P.S. : You can also directly use eqaution of trajectory and replace tanФ by 1.5 and u cosФ by 2