Question

A particle is projected with speed 10m/s at an angle 60 with the horizontal.Then the time after which it's speed becomes half of initial(take g=10m/s^2)

Answer 1

i hope this helps ....

Answer 2

At highest point the speed of particle = 10 Cos 60° = 5, means at highest point the velocity become half and then at that point that time t =u sin¢/g
t=10sin60°/10
=√3/2sec