A particle is projected with speed u at angle with
horizontal from ground. If it is at same height from
ground at time t, and ty, then its average velocity
in time interval t, to tz is
SOLVE WITH EXPLANATION PLEASE
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- u cos theta as it at the same height and their is no change
Explanation:
at maximum height v(y)is =0 and v(x)is equal to u cos theta
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