A particle is projected with speed v at an angle theta to the horizontal on an inclined surface making an angle phi (phi < theta) to the horizontal. Find an expression for its range along the inclined surface
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Answer:
R=
g
2V
o
2
cos
2
ϕ
sinθcos(θ+ϕ)
Explanation:
Given that
Speed of particle = Vo
Angle of particle from incline surface = θ
Angle of incline surface from horizontal =Φ
The formula for range R given as
If particle is moving upward
R=\dfrac{2V_o^2}{g}\dfrac{sin\theta cos(\theta +\phi ) }{cos^2\phi }R=
g
2V
o
2
cos
2
ϕ
sinθcos(θ+ϕ)
Time flight T
T=\dfrac{2V_osin\theta }{gcos\phi }T=
gcosϕ
2V
o
sinθ
Maximum height h
T=\dfrac{V_o^2sin^2\theta }{2gcos\phi }T=
2gcosϕ
V
o
2
sin
2
θ
Explanation:
hope it help
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