Question

A particle is projected with the initial speed u = 0 m/s from the top of the building at a time t = 0 sec. At a time = 5 sec the particle strikes the ground, find the height of the building

Answer 1

$<h2><font color = red > hey there$



$<font color = black > here we go....$



u = 0 m/s

t = 5s

a = 10 m/s^2


Using the second equation of motion ....


$s = ut + \frac{1}{2} at {}^{2}$



$s = \frac{1}{2} \times 10 \times 5 {}^{2}$



$s = 5 {}^{3} = 125m$



Hope it helps you

Thanks for asking.....



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