Question

The difference between the compound interest compounded annually and the simple interest on a certain sum for 2years at 15%per annum is ₹180. Find the sum.

Answer 1

Answer:

I'm not good at this

Step-by-step explanation:

I'm not good at this

Answer 2

Answer:

$Sum = > Rs. \: 8000$

Step-by-step explanation:

$Given:$

$t = n = 2 \: years \\ r = 15\%$

$The \: difference \: between \: C.I. \: and \\ \: S.I. = > Rs. \: 180$

$We \: all \: know \: that, \: \\ C.I. = A \: - \: P \\ and \: S.I. = \frac{P \times r \times t}{100}$

$Also \: we \: knew, \\ A \: = P(1 + \frac{r}{100} ) {}^{n} \\ Thus, \\ C.I. = P(1 + \frac{r}{100} ) {}^{n} - P \\ \\ Now... \\ C.I. = P(1 + \frac{15}{100} ) {}^{2} - P \\ C.I.=P ( \frac{115}{100} ) {}^{2} - P \\ C.I. = \frac{529p}{400} - P \\ C.I .= \frac{529P - 400P}{400} = \frac{129P}{400} \\ and \: S.I. = \frac{P \times 15 \times 2}{100} = \frac{30P}{100} \\ = \frac{3}{10} P \\ \\ ATQ... \\ C.I . - S.I .= Rs. \: 180 \\ = > \frac{129P}{400} - \frac{3P}{10} = Rs. \: 180 \\ = > \frac{129P - 120P}{400} = Rs. \: 180 \\ = > \frac{9P}{400} = Rs. \: 180 \\ = > P = Rs. \: \frac{180 \times 400}{9} \\ = > P = Rs \:. \: 8000$

Hope this clears up your confusion.

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