A particle is projected with velocity 10m/s at 60 angle. What is velocity at highest poin of path?
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At highest point the final velocity will be 15*cos45 = 10.6 m/sec in the horizontal direction (parallel to ground).
At highest point the y component of velocity becomes zero so only velocity in the horizontal direction remains.
At highest point the y component of velocity becomes zero so only velocity in the horizontal direction remains.
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