Question

A particle is projected with velocity (4i-9j)m/s. The acceleration in the region is constant and -10j m/s². The trajectory equation will be​

Answer 1

Answer:

Explanation:

6*10^-2J/T. Is the answer for it.

Answer 2

Answer:

y=-9/4x-(-10)x^2/v^2(9/4)^2

Explanation:

concept - using the projectile equation that is y=x tanθ / ( 2 u^2 cosθ^2).

given - velocity= (4i-9j)m/s

a=-10j m/s²

find = trajectory equation

explanation -

equation for trajectory motion

y=xtan θ-gx^2/2v^2cos^2 θ

put values in it

tan θ=vy/vx= -9/4

y=-9/4x-(-10)x^2/v^2(9/4)^2

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