Question

A particle is projected with velocity u at
an angle theta with the horizontal at t=0.
What is the magnitude of change in the
velocity of the particle when it is at
maximum height​

Answer 1

Answer:

At the time of projection, the particle's speed is u and the particle's speed at the highest point the particle's speed is ucosθ. So, the change in speed is,

Δu=u−ucosθ

Now, the initial velocity is,

u

=ucosθ

i

^

+usinθ

j

^

and the final velocity (at highest point) is,

v

=ucosθ

i

^

Therefore, the change in velocity is,

Δ

v

=

u

−

v

=ucosθ

i

^

+usinθ

j

^

−ucosθ

i

^

=usinθ

j

^

⇒∣Δ

v

∣=usinθ