Question

A particle is pushed along a horizontal surface in such a way that it starts with a velocity of 12m/s.Its velocity decreases at a uniform rate of
0.5m/s^2. [a] Find the time it will take to come to rest. [b] Find the distance covered by it before coming to rest?

Answer 1

initial velocity u of the particle = 12m/s
uniform  deceleration a = 0.5m/s²

at the time of rest velocity of the particle will be 0
let after time t s it will come to rest 
so using "v = u -at " equation we get 
t = 24 sec
let, before coming to rest it will move a distance s metre
so using "v² = u² - 2as" equation we get
s = 144 m 

Answer 2

Explanation:

s=144m..

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