A particle is released from a height h at a certain height its kinetic energy is two fifth of its potential energy the speed of the particle at that instant is
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total mechanical energy at hieght=k.e +p.e=mgh(as v=0)
total mechanical enegy at hieght at the point=k.e+p.e
=k.e+5/2k.e
=7/2k.e
by law of conservation of energy
mgh=7/2k.e
2*mgh=2*7/2k.e
mgh=7*1/2mv^2
gh=7/2v^2
2gh/7=v^2
square root (velocity at height/7)
=v
total mechanical enegy at hieght at the point=k.e+p.e
=k.e+5/2k.e
=7/2k.e
by law of conservation of energy
mgh=7/2k.e
2*mgh=2*7/2k.e
mgh=7*1/2mv^2
gh=7/2v^2
2gh/7=v^2
square root (velocity at height/7)
=v
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