A particle is released from a height h. At certain height its kinetic energy is three times its potential energy. Speed of particle at that instant is
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Answer:
total mechanical energy =mgH
Given
KE
PE
=
2
1
∴KE+PE=mgH
2PE+PE=mgH
∴PE=
3
1
mgH=mg(
3
H
)
∴ height from ground at this instant is
3
H
.
∴KE=
3
2 mgH
∴
2
1
mv
2
=
3
2 mgH
∴v=2
3
9H
is the velocity at that instant
Explanation:
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