Question

A particle is released from rest from a tower of height 3h the ratio of the intervals of time to cover three equal heights age is

Answer 1

Answer:

Explanation:

we know that

s = ut + (1/2)at2

 

here

u = 0

a = g

 

now for the first case, the total distance travelled in the 1second

 

s1 = (1/2)gt12

 

similarly the distance travelled after 2 ad 3 seconds respectively

s2 = (1/2).g.(t1 + t2)2

s3 = (1/2).g.(t1 + t2 + t3)2

 

so, the ratio of the height will be

s1 : s2 : s3 = 1 : 2 : 3 =  t12 : (t1 + t2)2 : (t1 + t2 + t3)2

or

 t1 : (t1 + t2) : (t1 + t2 + t3)  = 1 : √2 : √3

 

thus, we get

(t1 : t2 : t3)  =  1 : (√2 1) : (√3 √2