A particle is released from the top of a tower of height 150m and another ball is thrown vertically upwards with velocity 20m/s from a tower of height 50m at the same time. Assume both are in a same vertical line. Then time after which they collide to each other- (take g= 10m/s2)
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Let t be the time after which they collide
1st particle will travel
s1=(1/2)×10×t^2
2nd particle will travel s2=20t-(1/2)(10)t^2
s1 +s2+50=150
(1/2)×10×t^2+20t-(1/2)×10×t^2=100
20t=100
t=5 sec
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