Question

A particle is rotating on a circular path with initial angular velocity 2 rad/s and angular acceleration of 1 rad/s² then find it's net acceleration in m/s² after 2s if radius of path is 1m?
Please give the answer as soon as possible. Will be waiting eagerly for it.​

Answer 1

Answer:

It's net acceleration is $\sqrt{17}$ m/$s^{2}$

Explanation:

given:

angular velocity = 2 rad/s

angular acceleration = 1 rad/s²

radius = 1m

acceleration due to rotation = $\frac{V^{2} }{R}$

$\frac{2^{2} }{1}$ = 4

Therefore total acceleration = $\sqrt{4^{2} +1^{2} }$

                                              =$\sqrt{16 + 1}$

                                              =$\sqrt{17}$ m/$s^{2}$