Question

A particle is taken to a height r above the earth's surface, where r is the radius of the earth. The acceleration due to gravity there is

Answer 1

The value of acceleration due to gravity is $G \frac{M}{r^{2}}$

Explanation:

The particle which is taken to a height r more than earth’s surface and when r is the radius of earth.  

The acceleration due to gravity will be same as experienced by the particle on the earth’s surface. As the Gravitation Law put forth is uniform for the whole of the universe.  

Thereby, the acceleration due to gravity can be calculated as  

$a=\frac{F}{m}$

$\Rightarrow F=G\left(m \times \frac{M}{R^{2}}\right)$

Where,

m is the mass of object  

M is the mass of massive object  

G is the Gravitation constant with R is the distance between the two

$a=\frac{F}{m}$

$a=G \frac{M}{r^{2}}$

Answer 2

Answer:

2.45m/s²

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