Question

A particle is thrown horizontally from a tower of height H .particle crosses horizontal line passing through mid point at a distance equal to height of tower (foot of the tower is taken as origin) .find initial velocity of particle.

Answer 1

Explanation:

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Answer 2

Answer:

u = √gH

Explanation:

x displacement = h

y = h/2

H/2= 1/2 g t²

t= √{H/g}

x = ut

H = u × √{H/g}

u = √gH