Question

A particle is thrown over a triangle from one end of a horizontal base and gruzing the
vertical falls one the other end of the base. If , and 0, are the base angles of the
triangle and is the angle of projection, then
1) tan etano, tan,
2) tan tan, tan,
3) tan @ tan, - tano,
4) tano tan(0, 0)​

Answer 1

ANSWER

tanα+tanβ=xy+R−xy

tanα+tanβ=x(R−x)yR ...(i)

Equation of trajectory is

y=xtanθ[1−Rx]

or, tanθ=x(R−x)yR ...(ii)

From Eqs. (i) and (ii), we have

tanθ=tanα+tanβ