Question

A particle is thrown up with a speed of 40 m/s. the
maximum height attained by the particle is:
(Assume g = 10 ms-2)
a) 100m b ) 80 m c) 40 md) 20 m​

Answer 1

Answer:

option A is the answer I guess

Answer 2

Answer:

u=40m/s

v=0

g=-10m/s2

v2=u2+2as

0=40^2+2(-10)h

20h=1600

h=1600/20

h=80m

therefore , h=80m