Physics, asked by manasikolhe11126, 7 months ago

a particle is thrown upward with a velocity 48m/s. if g = 10m/s2, then the distance travelled by the particle during 5th second is
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Answers

Answered by lahari60
1

Explanation:

u=48m/s

g=10m/s²

s=48+(-10)(5-1/2)

s=48-45

=3m

Answered by PhysicistSam
0

Answer:

-9.8m(upward direction)

Explanation:

Here we use kinematics second equation..The answer will be in -ve

Hope u get it...

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