a particle is thrown upward with a velocity 48m/s. if g = 10m/s2, then the distance travelled by the particle during 5th second is
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Answers
Answered by
1
Explanation:
u=48m/s
g=10m/s²
s=48+(-10)(5-1/2)
s=48-45
=3m
Answered by
0
Answer:
-9.8m(upward direction)
Explanation:
Here we use kinematics second equation..The answer will be in -ve
Hope u get it...
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