Question

A particle is thrown upwards from ground at t=0. If the particle passes the same point at t=t1, and t =t2. Find the max. height attained by the particle.​

Answer 1

Answer:

Your ans. Is *h*

Explanation:

S or h =ut +1/2at^2

Given... t=t1. & t=t2

Therefore,, t1=t2

H=ut+1/2a(t1)^2

&

H=ut+1/2a(t2)^2

THEREFORE,, H=h.

Hope this is the right answer.