Question

A particle is thrown vertically up with initial
velocity of 60 m/s. The distance covered by the
particle in first two seconds of descent will be
(take g = 10 m/s2)
(1) 5 m
(2) 15 m
BY 20 m
(4) 40 m​

Answer 1

Answer:

at top it's velocity is 0

S=1/2gt2

s=5*4=20m