Question

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s, then maximum height attained by it

Answer 1

If we consider half height as starting point.
Then the initial velocity(u)=10m/s
Final velocity(v)= 0m/s
Acceleation(a)= -10m/s^2

Thus by using the formula
2as= v^2-u^2
-20s= -100
s= 5m

Now as half height was taken as starting point thus total height = 2x5
= 10m

Answer 2

v^2 - u^2 = 2aS
10^2 - u^2 = -2gH/2
-gH = 100 - u^2
-gu^2 / (2g) = 100 - u^2
u^2 / 2 = u^2 - 100
100 = u^2 / 2
u^2 = 200

H = u^2 / (2g)
= 200 / (2 × 10)
= 10 m

Maximum height attained by it is 10 m