Question

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it :-
(g=10m/s2)

Answer 1

Answer:

Let maximum height be H

From the formula, v

2

=u

2

−2gs

(10)

2

=u

2

−2gH/2=u

2

−gH ........(1)

For attaining maximum height, v=0

0=u

2

−2gH⇒u

2

=2gH

Putting the value of u

2

in (1),

100=2gH−gH=gH

H=

g

100

=

10

100

=10metre

Answer 2

Let maximum height be H

From the formula, v

2

=u

2

−2gs

(10)

2

=u

2

−2gH/2=u

2

−gH ........(1)

For attaining maximum height, v=0

0=u

2

−2gH⇒u

2

=2gH

Putting the value of u

2

in (1),

100=2gH−gH=gH

H=

g

100

=

10

100

=10metre