Question

A particle is thrown vertically upward with a velocity of 4 m per second the ratio of its acceleration after 1 second and 2 second of its motion is
a - 1
b - 2
c - 4.9
d - 9.8
pls answer fast with full explanation

Answer 1

ans- [a] 1

The whole throw-fall lasts only 0.81549s. (2*4/9.81)

So at time 1s and 2s, the particle is already back on ground. It is still subjected to gravitational acceleration g=9.81m/(s-s), although it is not accelerating, the effect of this acceleration is exhibited as weight force once on ground. And it is constant.

Answer 2

Answer Refer To attachment...☝☝

↪Hope this may helpful to uh ↩