a particle is thrown vertically upwards with certain velocity from the ground. The particle will reach the maximum height in 10 s. At 5s the particle is at a height of h from the ground. THe maximum height attained by the particle is
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A stone is thrown vertically upwards. When particle is at a height half of its maximum height, its speed is 10m/s; then the maximum height attained by the particle is: [g = 10m/s2]
(a) 8 m
(b) 10 m
(c) 15 m
(d) 20 m
4 years ago
Answers : (1)
(b)
Let h be maximum height to be attained by stone.
Velocity with which particle is thrown
u= √2gh
v^2=u^2+2gh
when H=h/2,u= √2gh,v=10 m/s g=-g
v^2-u^2= 2gH
2gh-100= 2g h/2
2 g h/2 =100
h =10 m.
Home » Forum » Mechanics » maximum-height-attained-by-the-particle
A stone is thrown vertically upwards. When particle is at a height half of its maximum height, its speed is 10m/s; then the maximum height attained by the particle is: [g = 10m/s2]
(a) 8 m
(b) 10 m
(c) 15 m
(d) 20 m
4 years ago
Answers : (1)
(b)
Let h be maximum height to be attained by stone.
Velocity with which particle is thrown
u= √2gh
v^2=u^2+2gh
when H=h/2,u= √2gh,v=10 m/s g=-g
v^2-u^2= 2gH
2gh-100= 2g h/2
2 g h/2 =100
h =10 m.
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