A particle is thrown verticaly up with speed of40m/s from the top of a buildig
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The question is slightly incomplete,but what possible information I can give, I am giving...
By the above statement we get:-
u=40m/s
v=0m/s
g=10m/s^2
By using 1st equation of motion:-
we get t = 4s
By using 2nd equation of motion:-
we get h = 80m
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