Question

a particle is thrown with a speed of 20m/s at an angle 45⁰ with the horizontal from a point on ground. then what is time of flight , range, max. height and time of ascent​

Answer 1

hlo  mate here is ur ans....

Given :-u=20 m/s

          θ=30 degrees

          g=10 m/s2

         We get  sinθ=sin30 = 1/2

         Maximum height reached   H = u2sin2θ​/2g

        2020×20×(1/2)^2/20  = 5m

pls mark as brainliest.....