Question

A particle is thrown with a speed u at angle of theta from the ground. Find the time of the flight

flight​

Answer 1

No acceleration is there in the horizontal direction so the horizontal component will always be the same.

V  

h

​  

=uCosθ

If angle of net velocity is β with horizontal so Tanβ=  

V  

h

​  

 

V  

v

​  

 

​  

,  V  

v

​  

=Vsinβ and V  

h

​  

=uCosθ  

So Tanβ=  

uCosθ

VSinβ

​  

=>V=uCosθ.secβ

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