Question

A particle is thrown with any velocity vertically upward, the distance travelled by the particle in first second of its decent is

Answer 1

4.9 meters .
S= 1/2 gt*2

Answer 2

Hi friend,

We know that,

S=ut +1/2 gt²
U=0

S= 1/2 ×9.8 ×(1)²

S=4.9 m

Hope this helped you a little!!!!