A particle is thrownwith any velocity vertically upward,what is the distance travelled by the particle in first second of it decent is ?
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Thank you for getting in touch with us for the answer of your query. This question can be solved by the Newton's second equation of motion.
During the first second of decent, initial velocity is u = 0
Applying the equation:
s = ut + 1/2 at2 (t square)
= 1/2 x 10 x 1
= 5m
The distance will be 5 meters. I hope this answer will be helpful for you.
During the first second of decent, initial velocity is u = 0
Applying the equation:
s = ut + 1/2 at2 (t square)
= 1/2 x 10 x 1
= 5m
The distance will be 5 meters. I hope this answer will be helpful for you.
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