Question

A particle is travelling on a straight line road in such a way that it covers half of the distance with a speed V. is it possible that it'S average speed will become 2V or greater if it covers the next half with the constant speed???? SOMEONE WHO WILL ANSWER THIS WILL BE FOLLOWED BY ME

Answer 1

let total distance of path is S ... for first half , time taken if tspeed = distance/time3 = S/2tt = S/6      .............1 for second half , time taken is T ...for first  T/2 it moves with 4.5speed = distance/time4.5 = 2x/T x = 4.5T/2   ...........2for second T/2 it moves with 7.57.5 = 2y/Ty = 7.5T/2       ..........3we have , x+y = S/2so(7.5+4.5)T = S/2T = S/24        ...............4total time taken during its motion is T+t Ttotal = T+t = S/24+S/6 = 5S/24total distance = Saverage speed = total distance/total time = S/5S/24 = 24/5 = 4.8m/s approve if u like my ans

Answer 2

no,, that is not possible

Let's take total distance travelled by vehicle as 2X
vehicle covers first half distance that is =X
speed =distance / time
time to travel first half distance= t1
t1 = X / V
vehicle covers next half distance with constant speed that means speed "V"does not changed.
time to cover next half distance by vehicle =t2
X= (next half distance 2X/2)
t2 =X / V

Average speed = Total distance / Total time
Total time = t1. + t2 = X/V+ X/ V
average speed = 2X / ( X/V+ X/V)
average speed = 2X / (2X / V)
hence average speed = V
V is less than 2V and and it is not changed.